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Wave Calculations

Year 10 (IGCSE) 🌊 Waves & Optics  Solve problems using v = fλ; understand diffraction and interference.

🌊 v = fλ: Advanced Problem Solving

The wave equation links three key wave quantities. You must be comfortable rearranging and using it in complex situations.

🌊 Wave Equation
$$v = f\lambda \qquad f = \frac{v}{\lambda} \qquad \lambda = \frac{v}{f} \qquad T = \frac{1}{f}$$
📡 Radio wave example: BBC Radio 1 broadcasts at 98.8 MHz. Speed = 3×10⁸ m/s.
λ = v/f = 3×10⁸ ÷ 98.8×10⁶ = 3.03 m
🔊 Sound example: A sound wave in air (340 m/s) has wavelength 0.85 m. Find frequency.
f = v/λ = 340 ÷ 0.85 = 400 Hz
🌊 Water waves: Period T = 4 s. Speed = 6 m/s. Find wavelength.
f = 1/T = 0.25 Hz. λ = v/f = 6/0.25 = 24 m

🔊 Diffraction

Diffraction is the spreading of waves when they pass through a gap or around an obstacle. It is most noticeable when the gap size ≈ the wavelength.

📻 Radio waves diffract around hills: Long wavelength (~1 km) radio waves diffract around hills and buildings easily — that's why you can receive AM radio in valleys!
💡 Light through a narrow slit: Visible light (wavelength ~500 nm) diffracts through tiny slits, creating bright and dark bands — a diffraction pattern.
📡 Mobile phone signals (GHz frequencies, short λ) struggle to diffract around buildings — that's why you get dead spots in cities!

⚡ Wave Interference

When two waves meet, they superpose (add together). This creates constructive or destructive interference.

🌊 Type📝 Condition📊 Result
✅ ConstructiveWaves in phase (peaks align)Amplitude doubles — louder/brighter
❌ DestructiveWaves out of phase (peak meets trough)Amplitude cancels — quieter/darker
🎧 Noise-cancelling headphones use destructive interference — they create a sound wave that is the exact opposite (inverted) of the noise around you, cancelling it out!
🎯 Ready to test yourself? Click the Quiz tab above to answer questions on this topic!
⚗️ 🌊 Wave Calculations (v, f, λ, T)